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Color.FromArgb Method

Returns RgbColor class instance constructed from all 4 channels (alpha, red, green, and blue).

Namespace: Aurigma.GraphicsMill
Assembly: Aurigma.GraphicsMill (in Aurigma.GraphicsMill.dll)

Syntax

Visual Basic

Public Shared Function FromArgb ( _
	alpha As Byte, _
	red As Byte, _
	green As Byte, _
	blue As Byte _
) As RgbColor

C#

public static RgbColor FromArgb(
	byte alpha,
	byte red,
	byte green,
	byte blue
)

Parameters

alpha: Type: System.Byte
Alpha channel value.

red: Type: System.Byte
Red channel value.

green: Type: System.Byte
Green channel value.

blue: Type: System.Byte
Blue channel value.

Return Value

RgbColor class instance constructed from given channels.

Remarks

You can also use extended version of this method, i.e. FromArgb32(Int32, Int32, Int32, Int32). If you do not care about alpha channel, you can also use FromRgb(Byte, Byte, Byte) method.

Examples

Visual Basic

Dim rgb As Aurigma.GraphicsMill.RgbColor = _
 Aurigma.GraphicsMill.Color.FromArgb(120, 255, 0, 0)

C#

Aurigma.GraphicsMill.RgbColor rgb = 
    Aurigma.GraphicsMill.Color.FromArgb(120, 255, 0, 0);

See Also

Reference